Explanation:
It is given that,
Wavelength of a beam of light in vacuum, [tex]\lambda_o=620\ nm[/tex]
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,
[tex]n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s[/tex]
(b) The wavelength of light in material,
[tex]\lambda=\dfrac{\lambda_o}{n}[/tex]
Let [tex]\lambda_1[/tex] is the wavelength of these waves in the liquid. So,
[tex]\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m[/tex]
Hence, this is the required solution.