Respuesta :

Answer:

A. vertex B

B. Side BC and BD

C. Angle EBD

Step-by-step explanation:

An angle is an undefined term in plane geometry.

  • The vertex of [tex]\angle 4[/tex] is B
  • The sides of [tex]\angle 1[/tex] are BC and BD
  • Another name for [tex]\angle 5[/tex] is [tex]\angle DBE[/tex].
  • [tex]\angle FBC[/tex] is a right angle
  • [tex]\angle EBF[/tex] is an obtuse angle
  • [tex]\angle ABC[/tex] is a straight angle.
  • [tex]\angle EBC = 144[/tex]
  • [tex]\angle ABE =13.5[/tex]

Vertex of [tex]\angle 4[/tex]

The vertex of an angle is the point where the rays that form the angle meet.

From the diagram, rays BE and BA meet at point B to form [tex]\angle 4[/tex].

Hence, the name of the vertex is B

Sides of [tex]\angle 1[/tex]

The sides of an angle are the rays or sides that form the angle

[tex]\angle 1[/tex] is formed by rays BC and BD

Hence, the sides are BC and BD

Another name for [tex]\angle 5[/tex]

An angle can be named by combining the sides and the vertex.

The sides of [tex]\angle 5[/tex] are DB and BE, while the vertex is B

This means that rays DB and BE meet at point B

Hence, another name is [tex]\angle DBE[/tex]

Classify the angles

Angles are classified based on the measure

[tex]\angle FBC[/tex] is a right angle, because [tex]\angle FBC = 90^o[/tex]

[tex]\angle EBF[/tex] is an obtuse angle because [tex]\angle EBF[/tex] is greater than [tex]90^o[/tex] but less than [tex]180^o[/tex]

[tex]\angle ABC[/tex] is a straight angle, because [tex]\angle ABC= 180^o[/tex]

Angle bisector

The line or ray that divides an angle into equal halves is an angle bisector.

Ray BE is an angle bisector, because it divides [tex]\angle DBA[/tex] into two equal halves.

Find [tex]\angle EBC[/tex]

We have:

[tex]\angle EBD = 36[/tex]

[tex]\angle DBC = 108[/tex]

[tex]\angle EBC[/tex] is calculated using:

[tex]\angle EBC = \angle EBD +\angle DBC[/tex]

[tex]\angle EBC = 108+36[/tex]

[tex]\angle EBC = 144[/tex]

Find [tex]\angle ABE[/tex]

We have:

[tex]\angle EBF = 117[/tex]

[tex]\angle DBC = 108[/tex]

[tex]\angle ABE[/tex] is calculated using:

[tex]\angle EBF = \angle ABE +\angle EBD + \angle ABF[/tex]

Where

[tex]\angle ABF = 90[/tex]

[tex]\angle ABE = \angle EBD[/tex]

So, we have:

[tex]117 = \angle ABE +\angle ABE + \angle 90[/tex]

[tex]117 = 2\angle ABE + 90[/tex]

Collect like terms

[tex]2\angle ABE =117 - 90[/tex]

[tex]2\angle ABE =27[/tex]

Divide both sides by 2

[tex]\angle ABE =13.5[/tex]

Read more about angles at:

https://brainly.com/question/13954458

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