Respuesta :

Given :

Some volume measurements :

[tex]0.75 \times 10^{-3}\ mL,\ 325\ \mu L,\ 4.11 \times 10^{-4}\ dL[/tex]

To Find :

Rank the measurements from largest to smallest.

Solution :

Now , [tex]1\ \mu l=10^{-3}\ ml[/tex].

Also , [tex]1\ dl=100\ ml[/tex].

So , the measurements in same units are :

[tex]0.75 \times 10^{-3}\ mL,\ 325 \times 10^{-3}\ mL , 4.11 \times 10^{-4} \times 100\ mL\\\\0.75\times 10^{-3}\ mL ,\ 325\times 10^{-3}\ mL ,\ 41.1\times 10^{-3}\ mL[/tex]

So , the order from highest to lowest is :

[tex]325\times 10^{-3}\ mL ,\ 41.1\times 10^{-3}\ mL ,\ 0.75\times 10^{-3}\ mL[/tex]

Hence , this is the required solution .

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