Given :
Some volume measurements :
[tex]0.75 \times 10^{-3}\ mL,\ 325\ \mu L,\ 4.11 \times 10^{-4}\ dL[/tex]
To Find :
Rank the measurements from largest to smallest.
Solution :
Now , [tex]1\ \mu l=10^{-3}\ ml[/tex].
Also , [tex]1\ dl=100\ ml[/tex].
So , the measurements in same units are :
[tex]0.75 \times 10^{-3}\ mL,\ 325 \times 10^{-3}\ mL , 4.11 \times 10^{-4} \times 100\ mL\\\\0.75\times 10^{-3}\ mL ,\ 325\times 10^{-3}\ mL ,\ 41.1\times 10^{-3}\ mL[/tex]
So , the order from highest to lowest is :
[tex]325\times 10^{-3}\ mL ,\ 41.1\times 10^{-3}\ mL ,\ 0.75\times 10^{-3}\ mL[/tex]
Hence , this is the required solution .