Answer:
71°
142°
Step-by-step explanation:
[tex] \because QS \: is \: the \: bisector \: of \: \angle \: PQR\\
\therefore m\angle RQS =m\angle PQS\\
\because m\angle RQS = 71\degree...(given) \\
\huge \red{ \boxed{\therefore m\angle PQS = 71\degree}} \\ \because \: m\angle \: PQR = m\angle PQS + m\angle RQS \\ \because \: m\angle \: PQR = 71\degree + 71\degree \\ \huge \purple{ \boxed{\therefore \: m\angle \: PQR = 142\degree}}[/tex]
