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31-08-2020
Mathematics

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Find the modulus of the following |9+40i|

Respuesta :

mahamnasir mahamnasir

05-09-2020

Answer:

modulus of |9+40i| is 41

Step-by-step explanation:

Let z = 9+40i

then

|z| = [tex]\sqrt{9^{2}+40^{2} }[/tex]

= [tex]\sqrt{81+1600}[/tex]

= [tex]\sqrt{1681}[/tex]

= 41

|z| = 41

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