Question

What is the formal charge of i in icl4

Answer 1

Answer:

Explanation:

in the Lewis structure of ICl4- there are total of 36 valence electrons. Since Iodine (I) is below Period 3 on the periodic table it can hold more than 8 electrons. ... Also note that you should put the ICl4- Lewis structure in brackets with as 1- on the outside to show that it is an ion with a negative one charge.

Answer 2

The formal charge present on the iodine atom of ICl₄ is -1.

How do we calculate formal charge?

Formal charge on any atom present in any compound will be calculated by using the below formula:

Formal Charge = (No. of valence electrons in neutral atom) - 1/2 (No. of electrons in covalent bond) - (No. of electrons in lone pair)

In the structure of ICl₄, 4 covalent bonds are present and for iodine atom no. of valence electrons in iodine is 7 and lone pair present on iodine is 2 means 4 electrons of lone pair is present. Structure is shown in the attached image.

On putting these values we get,

Formal charge = 7 - 1/2(8) - 4 = -1

Hence in iodine atom -1 charge is present.

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