Question

simply the question please​

Answer 1

Answer:  -2²¹

Step-by-step explanation:

Convert each term into a power of 2.

Use the product rule of adding the exponents and the quotient rule of subtracting the exponents.

$\dfrac{(-2)^3\times 4^4}{16^{-1}\times 8^{-2}}\quad =\dfrac{(-1)^3(2)^3(2)^{2(4)}}{(2)^{4(-1)}(2)^{3(-2)}}\qquad =-1^3\bigg(\dfrac{2^32^8}{2^{-4}2^{-6}}\bigg)$

$=-1(2^{3+8-(-4)-(-6)})\qquad =-1(2^{3+8+4+6})\qquad =-2^{21}$

Answer 2

Answer:

-2^21

Step-by-step explanation:

(-2)^3*4^4=-8*(2^2)^4=-1*2*4*2^8=-1*2^9*2^2=

=-1*2^11

(16)^-1*8^-2=2^-4*2^-6=2^-10

-1*2^11/2^-10=-1*2^11*2^10=-2^21