Answer:
Apparently this has been asked a few years ago, so I copied this answer from deepikakvvk06 - - all credit goes to them!
velocity of car 'B' after collision is 22.5m/s. //it's a conservation of momentum question
Explanation:
Let ,
mass = m
initial velocity = u
final velocity = v
here ,
m₁= 1500 kg
m₂=1000 kg
u₁ = 25 m/s
u₂ = 15 m/s
v₁ = 20 m/s
we have to find v₂ !!
v₂ is the velocity after collision
Here is a formula relating the values given ,
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
m₁u₁+m₂u₂ = 1500 × 25 + 1000 ×15
= 37500 + 15000
= 52500
m₁v₁ + m₂+v₂ = 1500 × 20 + 1000 × v₂
= 30000 + 1000v₂
m₁u₁+m₂u₂ = m₁v₁ + m₂+v₂
52500 = 3000 + 1000v₂
1000v₂ = 52500 - 30000
1000 v₂ = 22500
v₂ = 22500/1000
= 22.5 m/s
Thus, velocity of car 'B' after collision is 22.5m/s.