Answer:
Step-by-step explanation:
Let the two numbers be x and y. If the sum of the numbers is 65, then;
x+y = 65........ 1
Given twice the smaller number is 10 more than the larger number, this can be written as 2x = 10+y (taking x as the smallest and y as the largest)
Therefore 2x = 10+y
x = 10+y/2 ....... 2
Substitute equation 2 into 1 to have;
10+y/2 +y = 65
Find the LCM
(10+y+2y)/2 = 65
10+3y/2 = 65
cross multiply
10+3y = 130
3y = 130 -10
3y = 120
y = 120/3
y = 40
Since 2x =10+y
2x = 10+40
2x = 50
x = 50/2
x = 25
Therefore the two numbers are 40 and 25
