Question

A car accelerates uniformly from rest to a speed of 18 m/s in 12 seconds. Find the acceleration of the car over this period.

Answer 1

The correct answer is $1.5 m/ s^{2}$

Explanation:

In general terms, the acceleration refers to how velocity changes or increases. This is measured in meters per second squared ($m/s^{2}$) or similar units such as kilometers per hour squared ($km/h^{2}$). Moreover, to calculate acceleration it is necessary to subtract the initial velocity from the final velocity and then divide this into the time. The formula and operation are shown below:

$a (acceleration) = \frac{v (final velocity) - u (initial velocity)}{t (time)}$

$a= \frac{18 m/s - 0 m/s}{12 s}$    (Initial velocity is 0 m/s because the car was at rest)

$a = \frac{18 m/s}{ 12 s}$

$a = 1.5 m/s^{2}$

According to this, the acceleration of the car was $1.5 m/s^{2}$