Question

Consider the graphs of f (x) = x cubed and of g (x) = StartFraction 1 Over x cubed EndFraction. Are the composite functions commutative? Why or why not?

Answer 1

Answer:

c

Step-by-step explanation:

They are not commutative because the domains of f(x) and g(x) are different.

Answer 2

Answer: C

They are not commutative because the domains of f(x) and g(x) are different.

Step-by-step explanation: