[tex]( {5}^{2} - 1) \div 6 = [/tex]
[tex](25 - 1) \div 6 = [/tex]
[tex]24 \div 6 = 4[/tex]
Note:
Do the square first, and then you do mathematic operation between the parentheses. And, then do the
mathematic operation in the outside of parentheses.
Thank you.
Answer:
Step-by-step explanation:
[tex]\left(5^2-1\right)\div \:6\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5^2-1\right)\::\quad 24\\=24\div \:6\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:24\div \:6\:\\:\quad 4[/tex]