if anyone is good at algebra please help lol

Answer:
h(3x)=18x^2-12x-7
Step-by-step explanation:
[tex]h(x)=2x^2-4x-7\\h(3x) = ?\\\\h(3x) = 2(3x)^2 -4(3x)-7\\\\h(3x)=2\left(3x\right)^2-4\times\:3x-7\\\\h(3x)=3^2\times\:2x^2-4\times\:3x-7\\\\h(3x)=3^2\times\:2x^2-12x-7\\\\h(3x)=18x^2-12x-7[/tex]