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Answer:

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I think it may be 31%

Answer:

50%

Step-by-step explanation:

There are a total of 640 fries.

40% of them are crispy. Therefore, let C be the amount of crispy fries:

[tex]C=0.4(640)=256[/tex]

Thus, the amount of soggy fries S would be:

[tex]S=640-256=384[/tex]

The total of the crispy fries and the soggy fries is the sum of the fries not on the floor and on the floor. Let F denote on the floor and let NF denote not on the floor. Thus:

[tex]C=C_F+C_{NF}[/tex]

C is 256:

[tex]256=C_F+C_{NF}[/tex]

Same thing for soggy fries S:

[tex]S=S_F+S_{NF}\\[/tex]

S is 384, thus:

[tex]384=S_F+S_{NF}[/tex]

We are told that 80% of the soggy fries are on the floor. Therefore:

[tex]S_F=0.8(384)=307.2[/tex]

This means that the amount of soggy fries not on the floor is:

[tex]S_{NF}=S-S_F\\S_{NF}=384-307.2=76.8[/tex]

We are given that 32% of all the fries are not on the floor. Therefore:

[tex]NF=0.32(640)=204.8[/tex]

The total amount of fries not on the floor is the sum of the amount of crispy fries and soggy fries not on the floor. Thus:

[tex]NF=C_{NF}+S_{NF}[/tex]

We know that NF is 204.8 and that S(NF) is 76.8. Substitute:

[tex]204.8=C_{NF}+76.8[/tex]

Subtract 76.8 from both sides:

[tex]C_{NF}=128[/tex]

This means that out of the 256 crispy fries, only 128 of them are not on the floor.

This means that the amount on the floor is 256-128, or also 128.

Thus, the percentage of crispy fries on the floor is:

[tex]=\frac{128}{256}=50%[/tex]

Our answer is 50%

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