Question

Please help. I will give brainliest and 77 points

Answer 1

Answer:

________________

I think it may be 31%

Answer 2

Answer:

50%

Step-by-step explanation:

There are a total of 640 fries.

40% of them are crispy. Therefore, let C be the amount of crispy fries:

$C=0.4(640)=256$

Thus, the amount of soggy fries S would be:

$S=640-256=384$

The total of the crispy fries and the soggy fries is the sum of the fries not on the floor and on the floor. Let F denote on the floor and let NF denote not on the floor. Thus:

$C=C_F+C_{NF}$

C is 256:

$256=C_F+C_{NF}$

Same thing for soggy fries S:

$S=S_F+S_{NF}$

S is 384, thus:

$384=S_F+S_{NF}$

We are told that 80% of the soggy fries are on the floor. Therefore:

$S_F=0.8(384)=307.2$

This means that the amount of soggy fries not on the floor is:

$S_{NF}=S-S_F\\S_{NF}=384-307.2=76.8$

We are given that 32% of all the fries are not on the floor. Therefore:

$NF=0.32(640)=204.8$

The total amount of fries not on the floor is the sum of the amount of crispy fries and soggy fries not on the floor. Thus:

$NF=C_{NF}+S_{NF}$

We know that NF is 204.8 and that S(NF) is 76.8. Substitute:

$204.8=C_{NF}+76.8$

Subtract 76.8 from both sides:

$C_{NF}=128$

This means that out of the 256 crispy fries, only 128 of them are not on the floor.

This means that the amount on the floor is 256-128, or also 128.

Thus, the percentage of crispy fries on the floor is:

$=\frac{128}{256}=50%$

Our answer is 50%