Question

The three medals earned in the Olympics are the gold, silver, and bronze medals. In the 2014 Winter Olympics, the United States had 28 total medal winners. There were two more gold medals than sivler medals, and the number of bronze medals was four less than the sum of the number of gold and silver medals. How many winners were there of each type of medal? Gold: Silver: Bronze:

Answer 1

Answer:

Let x be the number of silver medals.

As there were two more gold medals than silver ones, gold medals are x+2

We also know that the number of bronze medals was 4 less than the sum of gold and silver, so if there are x + 2 of gold and x of silver, there are x+x+2-4 of bronze.

Now, we can do an equation, as we know there were a total of 28 medals:

x + x + 2 + x + x + 2 - 4 = 28

And we isolate x:

4x = 28

x = 28/4 = 7

There were 7 silver medals, so there were 9 gold ones (7-2) and 12 of bronze (9+7-4).

Answer 2

The number of Gold, Silver and Bronze medals are 9, 7 and 12 respectively.

Let the number of silver medals = s

Let the number of good medals = s + 2

Let the number of bronze medals = 2s - 2

Total medals = 28

Therefore, the value for each medal will be:

s + s+2 + 2s-2 = 28

Collect like terms

4s = 28 - 2 + 2

4s = 28

s = 28/4 = 7

Silver medals = 7

Gold medals = s + 2 = 7 + 2 = 9

Bronze medals = 2s - 2 = 2(7) -2 = 14 - 2 = 12

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