Respuesta :

Answer:

The answer is

[tex]{f}^{ - 1} (x) = \sqrt{ \frac{x - 3}{6} } [/tex]

Step-by-step explanation:

f(x) = 6x² + 3

To find the inverse of the function above equate it to y

That's

f(x) = y

So we have

y = 6x² + 3

Next interchange the variables that's x becomes y and y becomes x.

x = 6y² + 3

Next make y the subject

Subtract 3 from both sides

That's

6y² + 3 - 3 = x - 3

6y² = x - 3

Divide both sides by 6

That's

[tex] {y}^{2} = \frac{x - 3}{6} [/tex]

Next find the square root of both sides

[tex]y = \sqrt{ \frac{x - 3}{6} } [/tex]

We have the final answer as

[tex] {f}^{ - 1} (x) = \sqrt{ \frac{x - 3}{6} } [/tex]

Hope this helps you

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