Respuesta :
Answer:
Nitrogen
Explanation:
Hello,
In this case, for the given reaction we first need to assign the oxidation state for each species in the chemical reaction:
[tex]Sn ^{2+}(aq) + (N^{-3}H^+_4)^ +(aq) \rightarrow Sn^0(s) + (N^{5+}O_3^{2-})^ -(aq)[/tex]
In such a way, since the tin is decreasing its oxidation state it is being reduced whereas the nitrogen is being oxidized as its oxidation state is being increased from -3 to +5.
Best regards.
The element which is oxidized in the redox reaction shown below is Nitrogen.
Sn²⁺(aq) + NH⁴⁺(aq) → Sn(s) + NO₃⁻(aq)
In this scenario, the oxidation state of Sn changed from +2 to 0 while the
oxidation state of Nitrogen changed from -3 to +5. The Nitrogen(N) present
in the equation experienced an increase in the oxidation state which means
it was oxidized.
The Tin(Sn) on the other hand experienced a reduction in the oxidation state
which means it was reduced.
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