Respuesta :

Answer:

The angular acceleration of the top is 0.18 rad/s²

Explanation:

Given;

angular velocity of the top, ω = 16 rad/s

time it takes to come to a complete stop, t = 88.9s

The angular acceleration of the top, is calculated as;

[tex]\alpha = \frac{\omega}{t}[/tex]

α is the angular acceleration

ω is angular acceleration

t is the time

[tex]\alpha = \frac{\omega}{t}\\\\\alpha = \frac{16}{88.9}\\\\\alpha =0.18 \ rad/s^2[/tex]

Therefore, the angular acceleration of the top is 0.18 rad/s²

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