Question

Consider the following redox reaction: Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq). How many moles of electrons are exchanged?

Answer 1

Answer:

1 mol of electron is exchanged. The mol of electrons that is released by the iron, is gained by the silver.

Explanation:

We need to determine the half reactions:

Ag⁺ → Ag

These is the reduction reaction, where Silver decreases the oxidation state. It gained 1 mol of e⁻

Fe²⁺ → Fe³⁺

In this case, iron increases the oxidation state, from +2 to +3. It has released 1 mol of electrons. This is the oxidation reaction.

The complete redox is:

Ag⁺ + 1e⁻ → Ag

Fe²⁺ → Fe³⁺ + 1e⁻

Ag⁺(aq) + 1e⁻ + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq) + 1e⁻

The electrons will be cancelled.

Answer 2

In the redox reaction Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq),

1 mole of electrons is exchanged.

Let's consider the following balanced redox reaction.

Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq).

We can identify both half-reactions.

• Reduction: Ag⁺(aq) + 1 e⁻ ⇌ Ag(s)
• Oxidation: Fe²⁺(aq) ⇌ Fe³⁺(aq) + 1 e⁻

We can conclude that:

• In the reduction, 1 mole of Ag⁺ gains 1 mole of electrons to form 1 mole of Ag.
• In the oxidation, 1 mole of Fe²⁺ loses 1 mole of electrons to form 1 mole of Fe³⁺
• All in all, 1 mole of electrons is exchanged.

In the redox reaction Ag⁺(aq) + Fe²⁺(aq) ⇌ Ag(s) + Fe³⁺(aq),

1 mole of electrons is exchanged.

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