Answer:
The volume flow rate of the pipe is 1.41 x 10⁻³ m³/s
Explanation:
Given;
velocity of the fluid, v = 2.0 m/s
diameter of the pipe, d = 3.0 cm = 0.03 m
The volume flow rate is given by;
Q = Av
Where;
A is the area of the pipe
v is the velocity of the fluid
circular surface Area of the pipe is given by;
A = ¹/₄ πd²
A = ¹/₄ π(0.03)² = 7.07 x 10⁻⁴ m²
Q = (7.07 x 10⁻⁴)(2)
Q = 1.41 x 10⁻³ m³/s
Therefore, the volume flow rate of the pipe is 1.41 x 10⁻³ m³/s
