Respuesta :
Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}[/tex]
Option D is the correct option.
Step-by-step explanation:
Given, x = 2 and y = 4
[tex] \sf{(2x + 3y) \div 4 - 2}[/tex]
plug the value of x and y
⇒[tex] \sf{ (2 \times 2 + 3 \times 4) \div 4 - 2}[/tex]
Multiply the numbers which are inside the bracket
⇒[tex] \sf{(4 + 12) \div 4 - 2}[/tex]
Add the numbers which are inside the bracket
⇒[tex] \sf{16 \div 4 - 2}[/tex]
Divide 16 by 4
⇒[tex] \sf{4 - 2}[/tex]
Subtract 2 from 4
⇒[tex] \sf{2}[/tex]
Hope I helped!
Best regards! :D
Answer:
2 (D)
Step-by-step explanation:
(2x+3y)÷4-2 you replace the variables with the matching numbers, and then multiply them by the number next to them.
(4+12)÷4-2 you add the numbers together
16÷4-2 you divide 16 by 4
4-2 you subtract to
2 this is your answer