Respuesta :

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{2}}}}}[/tex]

Option D is the correct option.

Step-by-step explanation:

Given, x = 2 and y = 4

[tex] \sf{(2x + 3y) \div 4 - 2}[/tex]

plug the value of x and y

⇒[tex] \sf{ (2 \times 2 + 3 \times 4) \div 4 - 2}[/tex]

Multiply the numbers which are inside the bracket

⇒[tex] \sf{(4 + 12) \div 4 - 2}[/tex]

Add the numbers which are inside the bracket

⇒[tex] \sf{16 \div 4 - 2}[/tex]

Divide 16 by 4

⇒[tex] \sf{4 - 2}[/tex]

Subtract 2 from 4

⇒[tex] \sf{2}[/tex]

Hope I helped!

Best regards! :D

Answer:

2 (D)

Step-by-step explanation:

(2x+3y)÷4-2 you replace the variables with the matching numbers, and then multiply them by the number next to them.

(4+12)÷4-2 you add the numbers together

16÷4-2 you divide 16 by 4

4-2 you subtract to

2 this is your answer

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