Thanks for the help!

Answer:
A
Step-by-step explanation:
So we have the piecewise function:
[tex]f(x)= \begin{cases}\sqrt{2x} & \text{if }x<3 \\2x+10 & \text{if }3\leq x<8\\42&\text{if } x\geq 8\end{cases}[/tex]
And we want to find f(8).
Since our input value is 8, choose the equation that fits our input.
The first equation demand x to be less than 3. 8 is not less than 3, so we won't use that.
The second equation demand x to e greater than or equal to 3 and less than 8. 8 is not less than 8. So, we won't use that.
The third equation demands x to be greater than or equal to 8. 8 is greater than or equal to 8, so we'll use the third equation.
So:
[tex]f(x)=42\text{ if }x\geq 8[/tex]
[tex]f(8)=42[/tex]
There're nothing more to do, we're done :)
The answer is A.
Edit: Improved Format