How do I solve this?

Hi there! Hopefully this helps!
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[tex]\frac{175-172}{\frac{29}{\sqrt{20} } }[/tex]
Subtract 172 from 175 to get 3.
[tex]\frac{3}{\frac{29}{\sqrt{20} } }[/tex] ≈ 0.462634754
Factor [tex]20=2^{2} \times 5[/tex]. Rewrite the square root of the product [tex]\sqrt{2^{2} \times 5 }[/tex] ≈ [tex]4.472135955[/tex] as the product of square roots [tex]\sqrt{2^{2} } \sqrt{5}[/tex] ≈ 4.472135955. Take the square root of [tex]2^{2}[/tex] ≈ [tex]4[/tex]
[tex]\frac{3}{\frac{29}{2\sqrt{5} } }[/tex]
Rationalize the denominator of [tex]\frac{29}{2\sqrt{5} }[/tex] ≈ [tex]6.484597135[/tex] by multiplying numerator and denominator by [tex]\sqrt{5}[/tex] ≈ [tex]2.236067977.[/tex]
[tex]\frac{3}{\frac{29\sqrt{5} }{2(\sqrt{5} )^{2} } }[/tex]
The square of [tex]\sqrt{5}[/tex] ≈ [tex]2.236067977[/tex] is 5.
[tex]\frac{3}{\frac{29\sqrt{5} }{2 \times 5 } }[/tex] ≈ [tex]0.462634754[/tex]
Multiply 2 and 5 to get 10.
[tex]\frac{3}{\frac{29\sqrt{5} }{10 } }[/tex] ≈ [tex]0.462634754[/tex]
Divide 3 by [tex]\frac{29\sqrt{5} }{10}[/tex] ≈ 6.484597135 by multiplying 3 by the reciprocal of [tex]\frac{29\sqrt{5} }{10}[/tex] ≈ [tex]6.484597135.[/tex]
[tex]\frac{3\times 10}{29\sqrt{5} }[/tex] ≈ [tex]0.462634754[/tex]
Rationalize the denominator of [tex]\frac{3\times 10}{29\sqrt{5} }[/tex] ≈ 0.462634754 by multiplying numerator and denominator by [tex]\sqrt{5}[/tex] ≈ [tex]2.236067977.[/tex]
[tex]\frac{3\times 10\sqrt{5} }{29(\sqrt{5})^{2} }[/tex] ≈ [tex]0.462634754[/tex]
The square of [tex]\sqrt{5}[/tex] ≈ [tex]2.236067977[/tex] is 5.
[tex]\frac{3\times 10\sqrt{5} }{29 \times {5} }[/tex] ≈ [tex]0.462634754[/tex]
Multiply 3 and 10 to get 30.
[tex]\frac{30\sqrt{5} }{29 \times {5} }[/tex] ≈ [tex]0.462634754[/tex]
Multiply 29 and 5 to get 145.
[tex]\frac{30\sqrt{5} }{145 }[/tex] ≈ [tex]0.462634754[/tex]
[tex]\frac{175-172}{\frac{29 }{\sqrt{20} } } = \frac{3}{\frac{29}{\sqrt{20} } } =\frac{3\sqrt{20} }{29}=\boxed{\frac{6\sqrt{5} }{29} } = \boxed{0.463}[/tex]
Refer to the attached image for further explanation: