Answer:
Below
Step-by-step explanation:
Let y' = mx + b be the equation of the second line
● m is the slope
● b is the y-intercept
The lines are parallel so they have the
same slope.
● y' = 3x + b
The second line crosses the point with the coordinates (2,11)
Replace y' by 11 and x by 2 to find b
● 11 = 3×2 + b
● 11 = 6 + b
Substract 6 from both sides
● 11 - 6 = 6 + b -6
● b = 5
So
● y' = 3x + 5
