Respuesta :
Answer:
For y(-7) =6.4
The largest interval is between
[tex]-\infty \to -5[/tex]
For y(-2.5) = -0.5.
The largest interval is between
[tex]-5 \to 5[/tex]
For y(0) = 0
The largest interval is between
[tex]-5 \to 5[/tex]
For y(4.5) = -2.1.
The largest interval is between
[tex]-5 \to 5[/tex]
For y(14)= 1.7.
The largest interval is between
[tex]9 \to \infty[/tex]
Step-by-step explanation:
From m the question we are told that
The first order differential equation is [tex]\frac{y' - t}{ t^2 -25} = \frac{e^t}{t-9}[/tex]
Now the first step is to obtain the domain of the differential equation
Now to do that let consider the denominators
Now generally
[tex]t^2 - 25 \ne 0[/tex] side calculation
=> [tex]t\ne \pm5[/tex] [tex]t^2 - 25 = 0[/tex]
[tex]t = \pm 5[/tex]
Also [tex]t-9\ne 0[/tex] [tex]t -9 = 0[/tex]
=> [tex]t\ne 9[/tex] [tex]t= 9[/tex]
This means that this first order differential equation is discontinuous at
[tex]t = -5 , \ \ t = 5 \ \ t = 9[/tex]
[tex]This \ is \ illustrated \ below \ \\ ------------------\\\. \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \ \ \ \ \ \ \ \ \ \ \ \ \ |\\. \ -5 \ \ \ \ \ \ \ \ \ \ \ \ 5 \ \ \ \ \ \ \ \ \ \ \ \ \ 9[/tex]
So
For y(-7) =6.4
The largest interval is between
[tex]-\infty \to -5[/tex]
For y(-2.5) = -0.5.
The largest interval is between
[tex]-5 \to 5[/tex]
For y(0) = 0
The largest interval is between
[tex]-5 \to 5[/tex]
For y(4.5) = -2.1.
The largest interval is between
[tex]-5 \to 5[/tex]
For y(14)= 1.7.
The largest interval is between
[tex]9 \to \infty[/tex]