The correct option is B. Five dots belong in the electron dot diagram of a boron (B) atom. Boron has an atomic number of 5. In other words, the boron has 5 electrons. The first shell of a boron atom will therefore have two electrons, and the second shell will contain three.
In its three most frequent bonds, boron has a total of six electrons in the outermost shell: BH 3 start text, stop text, start subscript, 3, and end subscript. Because boron compounds are somewhat "electrons short," this also causes some abnormal characteristics in them.
Its atomic number is 5, and its electronic configuration is 2, 3, giving it the elemental symbol "B." It, therefore, has three electrons in the valence shell, two in the 2s and one in the 2p.
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