Question

expansion of (−1−2√3)^2​

Answer 1

(- 1 - 2√3)²

applicating (a - b)² = a² + b² - 2ab

a = - 1

b = 2√3

so:

(- 1 - 2√3)² =

(- 1)² + (2√3)² - 2(- 1)(2√3) =

1 + (2² * √3²) + 2(2√3) =

1 + (4 * 3) + 4√3

• ps. √x² = x

1 + 12 + 4√3 = 13 + 4√3