Question

Line g passes through the points (-2.6,1) and (-1.4,2.5), as shown. Find the equation of the line that passes through (0,-b) and (c,0).

Answer 1

Answer:

y=-1.25x-4.25

Step-by-step explanation:

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Answer 2

The equation of the line that passes through (0,-b) and (c,0) is

7y - 8x = 28

The formula for calculating the equation of a line in point-slope form is expressed as:

$y-y_0=m(x-x_0)$

m is the slope of the line

(x0, y0) is any point on the line

Given the coordinate points (0, -b) and (c, 0)

Since b  = -4 and c = -3.5

The required coordinate  points will be (0, 4) and (-3.5, 0)

Substitute the given parameters into the given formula for calculating the slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

$m=\frac{0-4}{-3.5-0} \\m = \frac{4}{3.5}\\m = 8/7$

Substitute m = 8/7 and the point (0, 4) into the expression $y-y_0=m(x-x_0)$

$y-4=\frac{8}{7} (x-0)\\7(y-4)=8x\\7y-28=8x\\7y-8x=28$

Hence the equation of the line that passes through (0,-b) and (c,0) is

7y - 8x = 28

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