Answer:
40 field goals
Step-by-step explanation:
Represent 2-point with x and 3-point with y;
Given
[tex]x = 3y[/tex]
[tex]2x + 3y =90[/tex]
Required
Determine x and y
[tex]x = 3y[/tex]
[tex]2x + 3y =90[/tex]
Substitute 3y for x in [tex]2x + 3y =90[/tex]
[tex]2(3y) + 3y = 90[/tex]
[tex]6y + 3y = 90[/tex]
[tex]9y = 90[/tex]
Divide both sides by 9
[tex]y = 10[/tex]
Substitute 10 for y in [tex]x = 3y[/tex]
[tex]x = 3 * 10[/tex]
[tex]x =30[/tex]
The number of field goals = x + y
[tex]x + y = 30 + 10[/tex]
[tex]x + y = 40[/tex]
Hence, the number of field goals is 40