Question

A bag contains 3 red apples and 6 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple and 2 yellow apple.

Answer 1

Step-by-step explanation:

$number \: of \: ways \: to \: select \: 3 \: out \: of \: 9 = {C}^{9}_3 = 84$

$ways \: to \: select \: 1red \: and \: 2yellow \: apples \: = {C}^{3}_1 \times {C}^{6}_2 = 3 \times 15 = 45$

Probability of selecting 1 red and 2 yellow apples = 45 / 84 = 0.53