Answer:
≈ 2.8 units
Step-by-step explanation:
Calculate the distance d using the distance formula
d = [tex]\sqrt{x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]
with (x₁, y₁ ) = (1, - 1) and (x₂, y₂ ) = (3, - 3)
d = [tex]\sqrt{(3-1)^2+(-3+1)^2}[/tex]
= [tex]\sqrt{2^2+(-2)^2}[/tex]
= [tex]\sqrt{4+4}[/tex]
= [tex]\sqrt{8}[/tex] ≈ 2.8 ( to the nearest tenth )
Answer: The answer is 2.8
Step-by-step explanation:
(1,-1)(3,-3) (those are the points shown in the graph)
The formula for finding distance is √(x2-x1)^2+(y2-y1)^2
= √(3-1)^2+(-3-(-1)^2
= √(2)^2+(-3+1)^2
= √4+(-2)^2
= √4+4
= √8
=2.828427125 (to the nearest tenth)
