I’m stuck and I don’t know what to do someone help please

Answer:
Step-by-step explanation:
1.
[tex]diameter = 6\:cm\\Radius = \:d/2\: =\: 6/2 = 3\:cm\\Height = 9\:cm\\\\Volume \:of\:a\:cone : \frac{1}{3} \pi r^2 h\\\\V = \frac{1}{3}\times 3.14 \times 3^2 \: \times 9\\\\V = \frac{1}{3} \times 3.14 \times 9 \times 9\\\\V = \frac{254.34}{3} \\\\Volume = 84.78cm^3[/tex]
2.
[tex]diameter =\: 6\:cm\\Radius= d/2 = 6/2 = 3\:cm\\Height = 9\:cm\\Volume = ?\\\\Volume \:of\:a \:cylinder = \pi r^2 h\\\\V = 3.14 \times 3^2 \times 9 \\\\V = 3.14 \times 9\times 9\\\\Volume = 254.34\:cm^3[/tex]
3.
The volume of a cone is (one third) of the volume of a cylinder which has the same height as the cone and the same base radius as the cone.
So, you need 3 (three) volumes of cone to fill the cylinder.