Question

A steam engine generating 5 hp is raising a load weighing 2000 lb.How high will thebload be raised in 10 s.​

Answer 1

Answer:

Explanation:

bi

Answer 2

The height raised by the load is 4.18 m.

Given data:

The power rating of steam Engine is, P = 5 hp = 5 × 745.7 = 3728.5 W.

The weight of load is, W' = 2000 lb = 2000 × 4.45 = 8900 N.

The time interval is, t = 10 s.

We know that the rate of doing any work is known as Power. So here the power will be equal to the work done to raise the load for 10 s of time. Then the expression is,

$P = \dfrac{W}{t}\\\\P = \dfrac{W' \times h}{t}$

Here, h is the height raised by load.

Solving as,

$3728.5 = \dfrac{8900 \times h}{10}\\\\h = 4.18 \;\rm m$

Thus, we can conclude that the height raised by the load is 4.18 m.

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