Step-by-step explanation:
Hey, there!!
Let me explain you very simply, ok.
Here, according to the question,
[tex]{x}^{2} = \frac{25}{144} [/tex]
X is square so, which finding the value of x you must take it to the right side (in root form ). so,
[tex]x = \sqrt{ \frac{25}{144} } [/tex]
Now, as we know that,
sq.root of 25 = 5
sq.root of 144 = 12
Now, you write it as,
[tex]x = \sqrt{ \frac{ {5}^{2} }{ {12}^{2} } } [/tex]
[tex]or \: x = \sqrt{( { \frac{5}{12} )}^{2} } [/tex]
Now, square root and (5/12) square ( square root , square gets cancelled).
You will get as,
[tex]x = \frac{5}{12} [/tex]
And its your simplified answer.
Hope it helps...