Assuming there are no reflections or dilations,
explain how you would write the equation of the
function whose graph is sketched below.
ty
4
-8
-4

Respuesta :

Answer:

Start with the parent function y=1/x^2.

Add 3 to x in the denominator, because the graph is shifted left 3. Add 1 to the fraction, because the graph is shifted up 1 unit.

Step-by-step explanation:

When a function is transformed, it means the function is either rotated, dilated, rotated or translated.

The equation of the function whose graph is sketched is:

[tex]f(x) = \frac{1}{(x + 3)^2} + 1[/tex]

The parent function is an inverse function of the form:

[tex]y = \frac 1{x^2}[/tex]

The parent function is shifted in two ways.

  1. 3 units left
  2. 1 unit up

When a function is shifted to the left, the rule is:

[tex](x,y) \to (x + h,y)[/tex]

Where:

[tex]h \to[/tex] number of units.

So, we have:

[tex](x,y) \to (x + 3,y)[/tex]

The function becomes

[tex]y' = \frac{1}{(x + 3)^2}[/tex]

When a function is shifted up, the rule is:

[tex](x,y) \to (x ,y+b)[/tex]

Where:

[tex]b \to[/tex] number of units.

So, we have:

[tex](x,y) \to (x ,y+1)[/tex]

The function becomes

[tex]y'' = \frac{1}{(x + 3)^2} + 1[/tex]

So, the graph of the function in the given graph (see attachment) is:

[tex]f(x) = \frac{1}{(x + 3)^2} + 1[/tex]

Read more about transformations at:

https://brainly.com/question/11707700

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