Answer: The concentration of the sulfuric acid is 0.09 M
Explanation:
Molarity is defined as the number of moles of solute dissolved per liter of the solution.
According to neutralization law,
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1[/tex] = basicity of sulphuric acid [tex](H_2SO_4)[/tex] = 2
[tex]M_1[/tex] = Molarity of sulphuric acid [tex](H_2SO_4)[/tex]solution = ?
[tex]V_1[/tex] = volume of sulphuric acid [tex](H_2SO_4)[/tex]solution = 25.0 ml
[tex]n_2[/tex] = acidity of sodium hydroxide [tex](NaOH)[/tex] = 1
[tex]M_2[/tex] = Molarity of sodium hydroxide [tex](NaOH)[/tex] = 0.150 M
[tex]V_2[/tex] = volume of sodium hydroxide [tex](NaOH)[/tex] = 30.0 ml
[tex]2\times M_1\times 25.0=1\times 0.150\times 30.0[/tex]
[tex]M_1=0.09M[/tex]
Thus the concentration of the sulfuric acid is 0.09 M
