Answer:
The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A
Explanation:
The Magnetomotive force (mmf) is given by the formula below
[tex]F_{M} = Hl\\[/tex]
where [tex]F_{M}[/tex] is the Magnetomotive force (mmf)
[tex]H[/tex] is the Magnetic field strength
[tex]l[/tex] is the magnetic length
The magnetic permeability μ is given by
μ = [tex]B / H[/tex]
Where [tex]B[/tex] is the Magnetic flux density
and [tex]H[/tex] is the Magnetic field strength
From the question,
[tex]B[/tex] = 1.2Wb/m^2
μ = 1600m
From μ = [tex]B / H[/tex]
∴[tex]H = B/[/tex]μ
[tex]H = 1.2 / 1600\\[/tex]
[tex]H = 7.5[/tex] × [tex]10^{-4}[/tex]A/m
Now, for the Magnetomotive force (mmf)
[tex]F_{M} = Hl\\[/tex]
From the question
[tex]l[/tex] = 1.5 m
∴ [tex]F_{M} = 7.5[/tex]×[tex]10^{-4}[/tex] × [tex]1.5[/tex]
[tex]F_{M} = 1.125[/tex]×[tex]10^{-3} A[/tex]
Hence, The mmf required is [tex]1.125[/tex]×[tex]10^{-3}[/tex] A
