Answer:
Distance AB is 18.79 units
Step-by-step explanation:
Given two points with coordinates as:
A= (-4,7)
B= (-12, -10)
To find:
Distance AB = ?
Solution:
To find the distance between two points with given coordinates, we can use Distance formula.
Distance formula is given as:
[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
where [tex](x_1, y_1)[/tex] and [tex](x_2, y_2)[/tex] are the two coordinates whose distance is to be find out.
[tex]x_1 = -4\\y_1 = 7\\x_2 = -12\\y_2 = -10[/tex]
[tex]AB = \sqrt{(-12-(-4))^2+(-10-7)^2}\\\Rightarrow AB = \sqrt{(-8)^2+(-17)^2}\\\Rightarrow AB = \sqrt{64+289}\\\Rightarrow AB = \sqrt{353}\\\Rightarrow \bold{AB = 18.79\ units }[/tex]
Distance AB is 18.79 units
Answer:
AB = 18.8 units
Step-by-step explanation:
If there are two points (x1,y1) and (x2,y2) on the coordinate plane.
distance between those two points = [tex]\sqrt{(x1-x2)^{2} + (y1-y2)^{2} }[/tex]
given points are
A= (-4,7)
B= (-12, -10)
[tex]AB = \sqrt{(-4 -(-12))^{2} + (7-(-10))^{2} }\\AB = \sqrt{(-4 +12)^{2} + (7+10)^{2} }\\AB = \sqrt{(8)^{2} + (17)^{2} }\\AB = \sqrt{64 + 289 }\\AB = \sqrt{353 }\\AB = 18.79[/tex]
Thus, length of AB is 18.79 units
since, value of hudredth of unit is 9 which is greater than 9 then rounding the value to nearest tenth of unit we increase the value at tenth of unit place by that is 7 becomes 8
length of AB to the nearest tenth of a unit is 18.9 units
