Answer:
Explanation:
Electric burner
For a 2.4 kW electric burner, the rate of energy consumption is 2.4 kW.
If efficiency is 73%, the cost of utilized energy is ...
($0.10 /kWh) / 0.73 ≈ $0.1370 per kWh utilized
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Gas burner
If the utilized energy provided by the gas burner is the same as the utilized energy of the electric burner, then the rate of energy consumption will be ...
2.4 kW(0.73)/(0.38) = 4.61 kW
In terms of kWh, the cost of gas is ...
$1.20/(105,500 kJ)·(1 kJ/(kW·s))·(3600 s/h) = $0.04095 /kWh
If efficiency is 38%, the cost of utilized gas energy is ...
($0.04095 /kWh) / 0.38 ≈ $0.1078 per kWh utilized
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The cost of gas is about 21% less per utilized joule.
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Comment on rates
The "unit rate" will depend on the unit chosen. In order to avoid unnecessary units conversions, we have elected to stick with kWh as the unit of energy for both cases. You may be asked for different units. We trust you or Google can make the necessary conversions.