Question

A charged particle has mass 1.20kg and charge negative 0.002C. It is moving. There is a uniform magnetic field of strength 0.25T pointing in the positive z direction present everywhere in the room. The particle experiences a magnetic force of 0.015N in the positive x direction. What is the velocity of the particle

Answer 1

Answer:

The velocity of the particle is 30 m/s.

Explanation:

The velocity can be found using Lorentz force:

$F = q*v \times B$

Where:

q: is the charge of the particle = 0.002 C

v: is the velocity of the particle

B: is the magnetic field = 0.25 T

F: is the magnetic force = 0.015 N

Since the magnetic field and the particle's velocity are orthogonal, the cross product is equal to the product of the absolutes values of v and B.

We have:

$F = q|v||B|$

$v = \frac{F}{qB} = \frac{0.015 N}{0.002 C*0.25 T} = 30 m/s$

Therefore, the velocity of the particle is 30 m/s.

I hope it helps you!