Respuesta :

Answer:

87.5 kJ

Explanation:

The potential energy stored in a stretch spring is given by the expression below

PE = Work = force * distance

So:

[tex]PE = (kx) * x[/tex]

This then simplifies to:

[tex]PE = kx^2[/tex]

where k is the spring constant= 140 N/m

Given that x= 25 m

Substituting our data into the expression for P.E stored we have

[tex]PE = 140*25^2\\\\PE= 140*625\\\\PE= 87500 J[/tex]

Hence the energy stored in the spring is 87.5kJ

ACCESS MORE