This is a very hard math question. Whoever answers correctly will get a brainlist too! Find the value of b. Then find the angle measures of the pentagon.
![This is a very hard math question Whoever answers correctly will get a brainlist too Find the value of b Then find the angle measures of the pentagon class=](https://us-static.z-dn.net/files/d42/61341e89b4d4122248909bb33ae6b7e7.png)
Answer:
Below
Step-by-step explanation:
The sum of the 5 angles is 540°
● b+(b+45)+90+(2b-90)+(3/2)b = 540
3/2 is 1.5
● b+b+45+90+2b-90+1.5b = 540
● 2b +45+2b+1.5b = 540
● 5.5 b +45 = 540
● 5.5b = 495
● b = 495/5.5
● b = 90°
Answer:
b = 90
Step-by-step explanation:
b + (b + 45) + 90 + (2b - 90) + (3/2)b = 540
b + b + 45 + 90 + 2b - 90 + (3/2)b - 90 = 540 - 90
b + b + 45 + 2b - 90 + (3/2)b = 450
2b + 2b + (45 * 2) + (2 *2b) - (90 * 2) + (2 * (3/2)b) = 450 * 2
2b + 2b + 90 + 4b - 180 + 3b = 900
11b - 90 = 900
11b - 90 + 90 = 900 + 90
11b = 990
b = 990 / 11
b = 90
check:
b + (b + 45) + 90 + (2b - 90) + (3/2)b = 540
90 + (90 + 45) + 90 + (2*90 - 90) + (3/2)*90 = 540
90 + 135 + 90 + 90 + 135 = 540
540 = 540 --- OK