Question

A student measures the mass of an 8 cm 3 block of brown sugar to be 12.9 g. What is the density of the brown sugar?

Answer 1

Answer:

$\huge\boxed{\rho=1.6125\dfrac{g}{cm^3}}$

Step-by-step explanation:

The formula of a density:

$\text{density}=\dfrac{mass}{volume}\Rightarrow\rho=\dfrac{m}{V}$

We have

$\text{mass}\ m=12.9g\\\\\text{volume}\ V=8cm^3$

Substitute:

$\rho=\dfrac{12.9g}{8cm^3}=\dfrac{12.9\cdot10}{8\cdot10}\dfrac{g}{cm^3}=\dfrac{129}{80}\dfrac{g}{cm^3}=1.6125\dfrac{g}{cm^3}$

Answer 2

The the density of the brown sugar is equal to $1.6125 \;g/cm^3$

Given the following data:

• Volume = 8 $cm^3$

• Mass = 12.9 grams

To find the density of the brown sugar;

Density can be defined as mass all over the volume of an object.

Simply stated, density is mass per unit volume of an object.

Mathematically, the density of a substance is given by the formula;

$Density = \frac{Mass}{Volume}$

Substituting the values into the formula, we have;

$Density = \frac{12.9}{8}$

Density =  $1.6125 \;g/cm^3$

Therefore, the the density of the brown sugar is equal to $1.6125 \;g/cm^3$

Find more information: brainly.com/question/5995838