Question

Find four consecutive integers such that twice the 3rd number decreased by the second number
is 8

Answer 1

Answer:

  5, 6, 7, 8

Step-by-step explanation:

Let x represent the 2nd number. Then x+1 represents the third number, and the given relation is ...

  2(x+1) -x = 8

  x +2 = 8

  x = 6

So, the numbers are 5, 6, 7, 8.

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Check

  2(7) -6 = 8 . . . . true