Answer:
Δx = 2.5 x 10⁻³ m = 2.5 mm
Explanation:
The distance between two consecutive fringes, also known as fringe spacing, in Young's Double Slit Experiment, is given as follows:
Δx = λL/d
where,
Δx = distance between consecutive fringes = ?
λ = wavelength of light = 500 nm = 5 x 10⁻⁷ m
L = Distance between slits and screen = 5 m
d = slit separation = 1 mm = 1 x 10⁻³ m
Therefore,
Δx = (5 x 10⁻⁷ m)(5 m)/(1 x 10⁻³ m)
Δx = 2.5 x 10⁻³ m = 2.5 mm
The separation between adjacent bright fringes on a screen 5 m from the slits is: 2.5 mm
We are given;
Wavelength of light; λ = 500 nm = 500 × 10⁻⁹ m
Distance of slit separation; d = 1mm = 0.001 m
Distance between slit and the screen; D = 5 m
Now, formula for fringe width is;
β = λD/d
Plugging in the relevant values gives;
β = (500 × 10⁻⁹ × 5)/0.001
β = 2.5 × 10⁻³ m
Converting to mm gives;
β = 2.5 mm
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