Question

If ∠R measures 18°, q equals 9.5, and p equals 6.0, then which length can be found using the Law of Cosines?

Answer 1

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Answer 2

If R measures 18°,q equals 9.5 ,p equals 6.0 then we can find the length of PQ which is r using the law of cosines.

What is law of cosines?

In trigonometric ratios law of cosines relates the lengths of the sides of a triangle to the cosine of one of its angles. Law of cosines is as under:

$c^{2} =a^{2} +b^{2} -2ab cos d$

where c is the side opposite to the angle given, a,b are the other sides and d is the angle given.

How to find length of triangle?

We have been given ∠R=18°, q equals 9.5 , p equals 6.0 then the length r can be calculated as under:

$r^{2} =p^{2} +q^{2} -2pq cos 18$

r=$\sqrt{p^{2} +q^{2} -2pq cos 18}$

Hence the length of r is equal to $\sqrt{p^{2} +q^{2} -2pq cos 18}$.

Learn more about trigonometry at https://brainly.com/question/24349828

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