Respuesta :
Answer:
Molar concentration = 2.35 M (Approx)
Explanation:
Given:
Density of solution = 1.151 g/ml
2.55 molal = 2.55 moles of solute/ kg
Find:
Molar concentration
Computation:
Molar mass of H2SO4 = 2(1.0079) + (32.066) + 4(15.999)
Molar mass of H2SO4 = 98.0778
Molar mass of H2SO4 = 98 g/mol (Approx)
Mass of solution = 2.55(98)g + 1000 g
Mass of solution = 1249.9 gm
Volume of solution = 1249.9 / 1.151 = 1086 ml
Volume of solution = 1.086 L
Molar concentration= 2.55 / 1.086
Molar concentration = 2.35 M (Approx)
Answer:
[H₂SO₄] = 2.35M
Explanation:
Our solute is the sulfuric acid → H₂SO₄
To determine the molar concentration we need the volume of solution.
Mass of solute: moles . molar mass
2.55 mol . 98 g/ 1 mol = 249.9 grams
Mass of solvent: 1 kg (we know this, because data refers about molality, moles of solute in 1kg of solvent)
Mass of solution = solute + solvent → 1000 g + 249.9 g = 1249.9 g
We apply density: Density = Mass / volume
1.151 g/mL = 1249.9 g / mL
mL = 1249.9 g/ 1.151 g/mL = 1086 mL
Molarity → mol/L → 2.55 moles/1.086L = 2.35 M