Respuesta :
Answer:
A. [tex]Claire = 20250[/tex]
B. [tex]Richard = 9350[/tex]
C. Height = 3.2 feet
D. Charges = $760
Step-by-step explanation:
Given
[tex]Claire = 50x^2 + 250[/tex]
[tex]Richard = 40x^2 + 350[/tex]
Solving (a): Claire's 20ft charges
In this case, x = 20
Substitute 20 for x in [tex]Claire = 50x^2 + 250[/tex]
[tex]Claire = 50(20)^2 + 250[/tex]
[tex]Claire = 50(400) + 250[/tex]
[tex]Claire = 20000 + 250[/tex]
[tex]Claire = 20250[/tex]
Solving (b): Richard's 15ft charges
In this case, x = 15
Substitute 20 for x in [tex]Richard = 40x^2 + 350[/tex]
[tex]Richard = 40(15)^2 + 350[/tex]
[tex]Richard = 40(225) + 350[/tex]
[tex]Richard = 9000 + 350[/tex]
[tex]Richard = 9350[/tex]
Solving (c): Height which they both charge the same;
This implies that
[tex]50x^2 + 250 = 40x^2 + 350[/tex]
Solving for x [Collect Like Terms\
[tex]50x^2 - 40x^2 = 350 - 250[/tex]
[tex]10x^2 = 100[/tex]
Divide both sides by 10
[tex]x^2 = 10[/tex]
Take square roots of both sides
[tex]x = \sqrt{10}[/tex]
[tex]x = 3.2ft[/tex] (Approximated)
Hence; Height = 3.2 feet
Solving (d): How much they charge when the charge the same amount.
Substitute 3.2 for x in any of the given equation
[tex]Claire = 50x^2 + 250[/tex]
[tex]Claire = 50(3.2)^2 + 250[/tex]
[tex]Claire = 50*10.24 + 250[/tex]
[tex]Claire = 512 + 250[/tex]
[tex]Claire = 762[/tex]
[tex]Richard = 40x^2 + 350[/tex]
[tex]Richard = 40(3.2)^2 + 350[/tex]
[tex]Richard = 40 * 10.24 + 350[/tex]
[tex]Richard = 409.6 + 350[/tex]
[tex]Richard = 759.6[/tex]
The reason for the difference is due to approximation
Hence, they both charge approximately 760