Answer:
The value is [tex]d = 0.000125 \ m[/tex]
Explanation:
From the question we are told that
The wavelength is [tex]\lambda = 500 \ nm = 500 *10^{-9 } \ m[/tex]
The distance is of the screen is [tex]D = 2.0 \ m[/tex]
The width of the fifth dark spot is [tex]y = 4.00 \ cm = 0.04 \ m[/tex]
Generally the width of a fringe is mathematically represented as
[tex]y = \frac{ n * \lambda * D }{d }[/tex]
=> [tex]0.04 = \frac{ 5 * 500 *10^{-9} * 2 }{d}[/tex]
=> [tex]d = \frac{ 5 * 500 *10^{-9} * 2 }{0.04}[/tex]
=> [tex]d = 0.000125 \ m[/tex]
