Question

A ball is rolling down a hill so that it accelerates at 3 m/s2. If it starts from rest and reaches a velocity of 9 m/s at the bottom of the hill, how long is the hill?

Answer 1

Answer:

13.5 m

Explanation:

Given:

v₀ = 0 m/s

v = 9 m/s

a = 3 m/s²

Find: Δx

v² = v₀² + 2aΔx

(9 m/s)² = (0 m/s)² + 2 (3 m/s²) Δx

Δx = 13.5 m